Practice: Fancy integral.

Calculus Level 2

Evaluate the following definite integral: ∫ ∫ 4 6 ( x − 1 ) d x ∫ 0 9 ( 2 x 2 + x + 3 ) d x 1 x d x \int^{\int_0^9 (2x^2+x+3)\,\mathrm dx}_{\int_{4}^6 (x-1)\,\mathrm dx}\dfrac{1}{x}\,\mathrm dx


The answer is 4.23682.

حكيم الفيلسوف الضائع by حكيم الفيلسوف الضائع , 35, Morocco

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1 solution

Biswajit Mishra
Nov 23, 2015

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