Practice

Algebra Level pending

( x 2 + x + 2 ) 2 ( a 3 ) ( x 2 + x + 2 ) ( x 2 + x + 1 ) + ( a 4 ) ( x 2 + x + 1 ) 2 = 0 (x^2+x+2)^2 - (a-3)(x^2+x+2)(x^2+x+1) + (a-4)(x^2+x+1)^2 = 0

Given that the equation above has at least one real root for a a in the interval p < a q p < a \leq q , find 3 q + p 3q + p .


The answer is 24.

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1 solution

Yash Dev Lamba
Jan 13, 2016

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