Practising Thermal Physics.
A thermodynamic system undergoes a cyclic process as shown in the figure. What amount of heat(in Joule) is absorbed or rejected in one cycle?
If heat ( ) is absorbed, enter the answer as .
If heat (
) is rejected, enter the answer as
.
- Give answer in
Joules
The answer is -314.
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1 solution
∆ W + ∆ U = ∆ Q (1st Law of thermo.)
In one complete cycle it is obvious that ∆ U = 0 (As it depends only on initial and final states)
∆ Q = ∆ W = Area under graph = π R 2 = 3 1 4 J (note R = 1 0 ) and we have to convert Volume from l i t r e s to m 3 .
Note work done is positive since we went clockwise.