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Algebra Level 1

2017 × ( 201 6 2 16 ) × 2015 2020 × ( 201 6 2 1 ) \dfrac{2017 \times (2016^2 -16) \times 2015}{2020 \times (2016^2 - 1)}

Find the value of the expression.

2011 2012 2013 2014 2015 2016 2017 2018

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3 solutions

Jason Chrysoprase
Aug 14, 2016

Relevant wiki: Multiplying and Dividing Monomials

Assume x = 2016 x = 2016 , so

2017 × ( 201 6 2 16 ) × 2015 2020 × ( 201 6 2 1 ) = ( x + 1 ) × ( x 2 16 ) × ( x 1 ) ( x + 4 ) × ( x 2 1 ) = ( x 2 1 ) × ( x + 4 ) × ( x 4 ) ( x + 4 ) × ( x 2 1 ) = x 4 \begin{aligned} \dfrac{2017 \times (2016^2 -16) \times 2015}{2020 \times (2016^2 - 1)} &= \dfrac{(x+1) \times (x^2 - 16) \times (x-1)}{(x+4)\times(x^2 -1)}\\ & = \dfrac{(x^2 - 1) \times (x+4) \times (x-4)}{(x+4)\times(x^2 -1)}\\ & = x - 4\\ \end{aligned}

So the answer is 2016 4 = 2012 2016 - 4 = \color{#D61F06}{\boxed{2012}}

Intelligent

Baldha Mulji - 4 years, 9 months ago
Chew-Seong Cheong
Aug 14, 2016

Q = ( 2017 ) ( 201 6 2 16 ) ( 2015 ) ( 2020 ) ( 201 6 2 1 ) = ( 2017 ) ( 2016 4 ) ( 2016 + 4 ) ( 2015 ) ( 2020 ) ( 2016 1 ) ( 2016 + 1 ) = ( 2017 ) ( 2012 ) ( 2020 ) ( 2015 ) ( 2020 ) ( 2015 ) ( 2017 ) = ( 2017 ) ( 2012 ) ( 2020 ) ( 2015 ) ( 2020 ) ( 2015 ) ( 2017 ) = 2012 \begin{aligned} Q & = \frac {(2017)\color{#3D99F6}{(2016^2-16)}(2015)}{(2020)\color{#D61F06}{(2016^2-1)}} \\ & = \frac {(2017)\color{#3D99F6}{(2016-4)(2016+4)}(2015)}{(2020)\color{#D61F06}{(2016-1)(2016+1)}} \\ & = \frac {(2017)\color{#3D99F6}{(2012)(2020)}(2015)}{(2020)\color{#D61F06}{(2015)(2017)}} \\ & = \frac {\cancel{(2017)}(2012)\cancel{(2020)}\cancel{(2015)}}{\cancel{(2020)}\cancel{(2015)}\cancel{(2017)}} \\ & = \boxed{2012} \end{aligned}

Armain Labeeb
Aug 27, 2016

Is this a photo ?

Jason Chrysoprase - 4 years, 9 months ago

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Yes, it is a photo.

Armain Labeeb - 4 years, 9 months ago

.................

Razzi Masroor - 4 years, 6 months ago

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