The rate at which Santa delivers presents to the children of the world can be described by the function , where is measured in hours and the rate is measured in presents given per hour. At Santa begins to deliver presents and he stops delivering presents once the rate of present giving reaches 0. There is one local maximum and one local minimum in the rate of present giving. The time exactly half way between the times when the local minimum and local maximum occur can be expressed in the form where and are positive integers. What is ?
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R ( t ) = − ( t − 1 0 ) 3 + π t 2 + 2 t + e 3
R ′ ( t ) = − 3 ( t − 1 0 ) 2 + 2 π t + 2
The above can be written in the form of a x 2 + b x + c : − 3 t 2 + ( 6 0 + 2 π ) t + ( − 3 0 0 + 2 )
Solutions to the above quadratic (maximum and minimum when R'(t) = 0) : t = 2 a − b + b 2 − 4 a c and 2 a − b − b 2 − 4 a c
Average of times: 2 2 a − b + b 2 − 4 a c + 2 a − b − b 2 − 4 a c
= 2 a − b
= − 6 − 6 0 − 2 π
= 1 0 + 3 π
a b + 1 2 = 3 × 1 0 + 1 2 = 4 2