Pressure can make you do wonders!

Chemistry Level 2

H 2 + C l 2 ⇌ 2 H C l \large H_2+Cl_2 \rightleftharpoons 2HCl If this reaction is carried out in a container at a pressure equal to atmospheric pressure, and pressure is increased by 5 5 times, then find the new value of K p K_p .

Given K p K_p for this reaction at atmospheric pressure is 12 12 .

Details and Assumptions:

K p K_p is Equilibrium Constant in terms of Pressure.

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1 2 1 5 12^{\frac{1}{5}} 1 2 5 12^5 12 12 60 60

Skanda Prasad by Skanda Prasad , 20, India

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2 solutions

Marc Fernández
Nov 12, 2017

H 2 + C l 2 ⇄ 2 H C l H_{2} + Cl_{2} \rightleftarrows 2HCl

K p = P H C l 2 P H 2 P C l 2 = P a t m 2 χ H C l 2 P a t m 2 χ H 2 χ C l 2 = χ H C l 2 χ H 2 χ C l 2 Kp=\frac{P_{HCl}^{2}}{P_{H_{2}}P_{Cl_{2}}}=\frac{P_{atm}^{2} \chi_{HCl}^{2}}{P_{atm}^{2} \chi_{H_{2}} \chi_{Cl_{2}}}=\frac{\chi_{HCl}^{2}}{\chi_{H_{2}} \chi_{Cl_{2}}}

So, Kp doesn't depend of pressure.

2 Helpful 0 Interesting 0 Brilliant 0 Confused
Rajdeep Das
Nov 10, 2017

Equilibrium constant of a reaction only depends on temperature.

2 Helpful 0 Interesting 0 Brilliant 0 Confused

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