An algebra problem by Sumukh Bansal

Algebra Level 2

Let function f f be defined as:

f ( x y ) = f ( x + y ) \large f(xy) = f(x+y)

If f ( 8 ) = 32 f(8) = 32 , find f ( 9 ) f(9) .


The answer is 32.

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2 solutions

Zach Abueg
Sep 23, 2017

Let x R x \in \mathbb{R} and y = 0 y = 0 . Then

f ( x 0 ) = f ( x + 0 ) f ( x ) = f ( 0 ) \begin{aligned} f(x \cdot 0) & = f(x + 0) \\ \implies f(x) & = f(0) \end{aligned}

meaning f ( x ) f(x) is a constant function. Thus, f ( 9 ) = f ( 8 ) = 32 f(9) = f(8) = \boxed{32}

Sumukh Bansal
Sep 21, 2017

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