Prime???

$(x-p_1)(x-p_2) = x^2-p_1x-p_2x+p_1p_2=x^2-(p_1+p_2)x+p_1p_2$ (where $p_1$ and $p_2$ are the two prime zeros of the function)

So we know that $p_1+p_2=63$ , and $p_1p_2=k$ . Because $63$ is odd, the only two primes that can add together to get $63$ are $2$ and $61$ . The product of these two primes is $2\times61=122$ .

This equation has two prime zeros and k us not given. So 63 can be devide into two primes. 63 is a odd number. Obviously 2 is one of them. And the other is 63-2=61 .

So our answer will be $\boxed {61\times2=122}$

By vieta's formula, Sum of the roots/ zeroes : 63/1 = 63 The only possible combination of prime numbers is 2 and 61. So product of zeroes : 122