3 / 2 5 / 2 5 / 3 7 / 3 = = = = 1 . 5 2 . 5 1 . 6 6 6 6 … 2 . 3 3 3 3 …
The above shows all equations of ratios of 2 distinct prime numbers. Is it true that the ratio of 2 distinct prime numbers is never an integer?
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Let us suppose that there are two integers x , y such that y x = k for some natural number k now we know that x = a y for some natural number a but a prime number has two factors 1 and the number itself. As x , y are distinct it is not possible for there to be two such primes
Consider two primes, p 1 and p 2
For p 2 p 1 to be an integer, p 1 must be a factor of p 2 . But this contradicts the fact that p 2 is a prime.
Hence, p 2 p 1 is never an integer.
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LET US SUPPOSE THAT the ratio of 2 distinct prime numbers is AN INTEGER.THEN IT HAS 1 MORE FACTOR AND THEREFORE CANNOT BE PRIME.