prime factor

$5!+6!=5!+5!(6)=5!(1+6)=5!(7)=1 \times 2 \times 3 \times 4 \times 5 \times 7$

Therefore, the largest prime factor is $\boxed{7}$ .

$5!$ $+$ $6!$ $=$ $1 \times (5!) + 6 \times (5!)$ $=$ $(1+6) \times (5!)$ = $(7) \times (5!)$ $=$ $1 \times 2 \times 3 \times 4 \times 5 \times 7$
So, the largest prime number is $\boxed{7}$
[ $Note:-$ for any integer
$n$ $\rightarrow$ $(n+1)! = (n+1) \times (n!)$ ]

5! + 6! = 5! + 6 * 5!
= 5! ( 1 + 6) = 7 * 5! [ n! = n*(n-1)! ] Now largest prime factor of n! <= n. Hence, in 5! we have the largest prime factor <=5. Here its = 5. But 7>5 and 7 is also a prime. Hence the answer is 7.