Prime factor

Determine the largest 3-digit prime factor of the integer ( 2000 1000 ) {{2000} \choose {1000}}


The answer is 661.

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1 solution

Otto Bretscher
Oct 4, 2015

Note that ( 2000 1000 ) = 2000 ! ( 1000 ! ) 2 {2000 \choose 1000}=\frac{2000!}{(1000!)^2} . Any prime number > 666 >666 will appear twice in the numerator and twice in the denominator, so, it will cancel out. But 661, the largest prime < 666 <666 , appears 3 times in the numerator but only twice in the denominator.

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