Prime factors

A number N when factorised can be written N = a 4 × b 3 × c 7 N = a^{4} \times b^{3} \times c^{7} . Find the number of perfect squares which are factors of N (the three prime numbers a,b,c>2)


The answer is 24.

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1 solution

In order that perfect square divides N, the powers of "a" can be 0,2,4 i.e. (3). Powers of "b" can be 0,2, i.e. (2). Power of "c" can be 0,2,4,6 i.e. (4)

Hence, a combination of these powers given 3 × 2 × 4. i . e . 24 \Rightarrow 3 \times 2 \times 4. \Longrightarrow i.e. 24 numbers

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