Prime Lands

A rich landlord had divided a big piece of land for his 3 3 sons, A , B , C A, B, C , so that each colored land had a prime area (in km 2 \text{km}^2 ) while the big lake in the middle would be shared among the 3 3 brothers, as shown above.

If the lake and A's areas were combined, it would cover 1 2 \frac{1}{2} of the whole land.

If the lake and B's areas were combined, it would cover 1 3 \frac{1}{3} of the whole land.

If the lake and C's areas were combined, it would cover 1 4 \frac{1}{4} of the whole land.

Let primes a , b , c a, b, c be the numerical values of the areas for the 3 owners respectively. Compute a × b × c a\times b\times c .


The answer is 385.

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1 solution

Let x x be total land mass and d d be the lake's area. Then a + b + c + d = x a+b+c+d = x .

Also, a + d = x 2 a+d = \dfrac{x}{2} .

b + d = x 3 b+d = \dfrac{x}{3}

c + d = x 4 c+d = \dfrac{x}{4}

Hence, adding up 3 3 equations, a + b + c + 3 d = x + 2 d = x 2 + x 3 + x 4 = 13 x 12 a+b+c+3d = x+2d = \dfrac{x}{2}+\dfrac{x}{3}+\dfrac{x}{4} = \dfrac{13x}{12} .

Thus, 2 d = x 12 2d = \dfrac{x}{12} . d = x 24 d = \dfrac{x}{24} .

Then a = 11 x 24 a = \dfrac{11x}{24} . b = 7 x 24 b = \dfrac{7x}{24} . c = 5 x 24 c = \dfrac{5x}{24} .

Since a , b , c a, b, c are prime, they can't have common factor, making x = 24 x=24 .

Therefore, a = 11 a=11 ; b = 7 b=7 ; c = 5 c=5 ; d = 1 d=1 .

Then a b c = 385 abc = \boxed{385} .

The statement "Let prime a a be the numerical value of the A's area" seems confusing to me. I think it would be better to just state that at the start that "The areas of A, B and C are a , b , a, b, and c c km 2 ^2 respectively, where a , b , c a, b, c are primes".

Calvin Lin Staff - 4 years, 3 months ago

Nice problem. At first I thought that by "... of the whole land" you meant all of A , B , C A,B,C but excluding the lake, but as that did not yield prime areas I tried again but with the lake included in the "whole land" and got the desired primes.

Brian Charlesworth - 4 years, 3 months ago

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