Prime Matrix

Algebra Level pending

A prime matrix is the numbers listed up to a prime (I just made this up because I am like that...). The general form is the function

f ( M ( f ( P n ) ) f(M(f(P_n))

where

f ( M ) f(M)

defines the matrix and

f ( P n ) f(P_n)

is equivalent to the prime-counting function

π ( x ) \pi(x)

The matrix is below for π ( 7 ) \pi(7) :

[ 1 2 3 4 5 6 7 ] \begin{bmatrix} 1 & 2 & 3\\ 4 & 5 & 6\\ 7 \end{bmatrix}

The question is this:

What's the probability that for any prime matrix, the matrix will always have twin primes?

Example:

For the matrix above, there are 2 2 pairs:

3 , 5 3, 5 and 5 , 7 5, 7

Out of 7 7 numbers, there are two pairs, therefore the probability is 2 7 \frac{2}{7} .

n π ( x ) \frac{n}{\pi(x)} 2 \frac{2}{\infty} t p n π ( x ) \frac{tp_n}{\pi(x)} 2 π ( x ) \frac{2}{\pi(x)}

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1 solution

Yajat Shamji
Aug 31, 2020

Denote the number of pairs of twin primes as t p n tp_n

Denote the prime matrix as the prime-counting function (since the prime matrix is, in essence, a visual representation of the prime-counting function).

Therefore the probability is

t p n π ( x ) \frac{tp_n}{\pi(x)}

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