Find the number of natural values for n>1 which satisfy that n 4 + 4 n is a Prime number .
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Good solution..
Relevant wiki: Sophie Germain Identity
An elementary application of the sophie-germain identity .
https://brilliant.org/problems/it-may-works-for-odd-numbers/?ref_id=1347822
Answer: 0
n 4 + 4 n can't be a Prime number.
We will discuss two cases:-
x is even ⟹ x 4 + 4 x = e v e n .
x is odd
if x is odd then we can write x as 2 n + 1 ; and the given equation can be written as
( 2 n + 1 ) 4 + 4 ( 2 n + 1 ) = ( 2 n + 1 ) 4 + 4 . ( 2 n ) 4
Which is not a prime.
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Answer: 0
n 4 + 4 n can't be a Prime number.
We will discuss two cases:-
x is even ⟹ x 4 + 4 x = e v e n .
x is odd
if x is odd then we can write x as 2 n + 1 ; and the given equation can be written as
( 2 n + 1 ) 4 + 4 ( 2 n + 1 ) = ( 2 n + 1 ) 4 + 4 . ( 2 n ) 4
Which is not a prime.