Prime no.s

Find the number of natural values for n>1 which satisfy that n 4 + 4 n n^{4} +4^{n} is a Prime number .


The answer is 0.

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2 solutions

Ossama Ismail
Jan 8, 2018

Answer: 0

n 4 + 4 n n^{4} +4^{n} can't be a Prime number.

We will discuss two cases:-

  1. x x is even x 4 + 4 x = e v e n . \implies x^4 + 4^x = even.

  2. x is odd

    if x x is odd then we can write x as 2 n + 1 x \ \text{as} \ 2n+1 ; and the given equation can be written as

( 2 n + 1 ) 4 + 4 ( 2 n + 1 ) = ( 2 n + 1 ) 4 + 4. ( 2 n ) 4 (2n +1)^4 + 4^{(2n+1)} = (2n +1)^4 + 4.(2^n)^4

Which is not a prime.

Good solution..

Shreyansh Mukhopadhyay - 3 years, 3 months ago
Aaryan Maheshwari
Dec 28, 2017

Relevant wiki: Sophie Germain Identity

An elementary application of the sophie-germain identity .

https://brilliant.org/problems/it-may-works-for-odd-numbers/?ref_id=1347822

Ossama Ismail - 3 years, 5 months ago

Answer: 0

n 4 + 4 n n^{4} +4^{n} can't be a Prime number.

We will discuss two cases:-

  1. x x is even x 4 + 4 x = e v e n . \implies x^4 + 4^x = even.

  2. x is odd

    if x x is odd then we can write x as 2 n + 1 x \ \text{as} \ 2n+1 ; and the given equation can be written as

( 2 n + 1 ) 4 + 4 ( 2 n + 1 ) = ( 2 n + 1 ) 4 + 4. ( 2 n ) 4 (2n +1)^4 + 4^{(2n+1)} = (2n +1)^4 + 4.(2^n)^4

Which is not a prime.

Ossama Ismail - 3 years, 5 months ago

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