Prime Possibilities

Find the sum of the first three (positive) prime values of α \alpha such that 2 α 2 1 2 \alpha ^2 -1 is also prime and ( 2 α 2 α ) 2 1 ( m o d 7 ) (2 \alpha ^2 -\alpha )^2 \equiv 1 \pmod 7 .


The answer is 22.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Chew-Seong Cheong
Feb 19, 2015

Using the following spreadsheet,

we find that the first three primes that satisfy the two conditions are 2 2 , 3 3 and 17 17 , therefore, the required answer is 2 + 3 + 17 = 22 2+3+17=\boxed{22} .

It's sad for a problem to be only solvable with a calculator or a computer, i didn't want to try long because, in my point of view, it had no interest.

Simon Boutin - 5 years, 11 months ago

I liked your spreadsheet, Chew-Seong! Exceptional analysis!

Guilherme Dela Corte - 6 years, 3 months ago

how to create these spreadsheets?

Dev Sharma - 5 years, 6 months ago

If you solve x^2=1 (mod 7) you can (with some work) narrow down alpha=1, 2, or 3 (mod 7). Then you can check that subset of primes (2,3,17,23,etc.) for the corresponding value of 2*alpha^2-1 to be prime to ensure all criteria are met. Doing so will find the answer Chew-Seong Cheong found using the spreadsheet, albeit with a little more labor. Sorry for the lack of a proper solution using Latex ;p

Jonathan Hocker - 4 years, 7 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...