Primes and bases

The minimum value of $D$ is 1 because of the following:

If $P$ could be represented in base $B$ with $D = 0$ , then this implies that $P$ is divisible by $B$ because if $P$ is represented in base $B$ as $ACFED \rightarrow ACFE0$ then $\frac{ACFE0}{B} = ACFE$

Therefore

$D = 0$ implies that $P$ is divisible by a number other then 1 and itself, which contradicts the definition of a prime number

Therefore

The minimum value of $D$ is 1

I apologize for my lack of skill with LaTeX by the way haha