Probability 2
A box B1 contains 1 white ball, 3 red balls and 2 black balls. Another box B2 contains 2 white balls, 3 red balls and 4 black balls. A third box B3 contains 3 white balls, 4 red balls and 5 black balls.
If 1 ball is drawn from each of the boxes B1, B2 and B3, the probability that all 3 drawn balls are of the same color is,
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
P(all W)=(1/6)x(2/9)x(3/12)=6/648
P(all R)=(3/6)x(3/9)x(4/12)=36/648
P(all B)=(2/6)x(4/9)x(5/12)=40/648
P(same color)=(6+36+40)/648
=82/648