Probability

Die A has 4 red and 2 white faces, whereas die B has 2 red and 4 white faces. A fair coin is flipped once. If it lands on heads, the game continues with die A; if it lands on tails, then die B is to be used. Find the probability of red at any throw

2/3 1/2 1/4 1/3

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Nelson Mandela
Dec 31, 2014

Please correct me if I am wrong.

so I took 2 cases. one with heads and one with tails. in the first case I got, 1/2 x (2/6) and in the second case I got 1/2 x (4/6) the sum of them I got 1/2.

Yes I did exactly the same except I simplified the fractions

Curtis Clement - 6 years, 5 months ago

you are right

Mahimn Bhatt - 6 years, 5 months ago
Sigmund Dela Cruz
Mar 18, 2015

probability of dice B is 1/3 and the probability of dice A is 2/3 since there is 50% chance that the probability of the red face of dice B is 1/3 and 50% chance that the probability of red surface of dice A is 2/3, we can't conclude 1 probability of dice A/B so using STAT i get the central tendency of the probability of dice A and dice B which is 3/3 divided by 2 which is 1/2 is the conclusive answer.

Mark Dave Martin
Jan 25, 2015

This is my way of solving the problem. (I'm sorry if you find this erroneous; though I've come up with the answer.) In the case of A, the probability of red color to appear would be 2/3. Whilst in the case of B is 1/3. I totted them up and the result was 3/3. Since it mentioned "at any throw" condition, I divided the result into two. Thus 3/3 or 1 divided by 2 equals 1/2.

same here, probability of dice B is 1/3 and the probability of dice A is 2/3 since there is 50% chance that the probability of the red face 1/3 and 50% chance that the probability of red surface is 2/3, we can't conclude only probability of dice A/B so using STAT i get the central tendency of the probability of dice A and dice B which is 3/3 divided by 2 which is 1/2 is the conclusive answer.

Sigmund Dela Cruz - 6 years, 2 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...