An integer from 100 through 999, inclusive, is to be chosen at random. What is the probability that the number chosen will have 0 as at least 1 digit?
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There are 9 0 0 numbers and in 1 0 0 − 1 9 9 , there are 1 9 zeroes. Since there are 9 of the identical set, that means the probability is 9 0 0 1 9 × 9 making the answer 9 0 0 1 7 1 .
Note: It is also 19%, but I chose not to simplify it for the means of the problem in case someone divided wrong but got the right fraction.