Certain types of traders attempt to repeatedly buy and sell the same asset for a profit over a short time period, such as high-frequency “market makers”. For example, if you can repeatedly sell a stock for $8.50 and buy it for $8.49, you will make $0.01 each time. This is known as arbitrage.
If this transaction succeeds with probability 99%, about how many times can this transcation be executed before the probability of at least one failure exceeds 50%?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Since the probability of any transaction succeeding is 0 . 9 9 , the probability of N [independent] transactions all succeeding will be 0 . 9 9 N . Therefore, the probability of at least one failure is 1 − 0 . 9 9 N .
If this exceeds 0 . 5 0 , then we can solve for N as 1 − 0 . 9 9 N > 0 . 5 0 . 9 9 N < 0 . 5 N ⋅ ln ( 0 . 9 9 ) < ln ( 0 . 5 ) N > ln ( 0 . 9 9 ) ln ( 0 . 5 ) ≈ 6 8 . 9 7
It follows that the smallest value of N is 6 9 . Looking at the given values, the nearest choice is 7 0 .