Probability and Statistics in Quant Finance

Certain types of traders attempt to repeatedly buy and sell the same asset for a profit over a short time period, such as high-frequency “market makers”. For example, if you can repeatedly sell a stock for $8.50 and buy it for $8.49, you will make $0.01 each time. This is known as arbitrage.

If this transaction succeeds with probability 99%, about how many times can this transcation be executed before the probability of at least one failure exceeds 50%?

70 30 50 10

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1 solution

Brian Moehring
Jun 29, 2018

Since the probability of any transaction succeeding is 0.99 0.99 , the probability of N N [independent] transactions all succeeding will be 0.9 9 N 0.99^N . Therefore, the probability of at least one failure is 1 0.9 9 N . 1 - 0.99^N.

If this exceeds 0.50 0.50 , then we can solve for N N as 1 0.9 9 N > 0.5 1 - 0.99^N > 0.5 0.9 9 N < 0.5 0.99^N < 0.5 N ln ( 0.99 ) < ln ( 0.5 ) N\cdot \ln(0.99) < \ln(0.5) N > ln ( 0.5 ) ln ( 0.99 ) 68.97 N > \frac{\ln(0.5)}{\ln(0.99)} \approx 68.97

It follows that the smallest value of N N is 69 69 . Looking at the given values, the nearest choice is 70 \boxed{70} .

Thank you, you Brilliant!

Kevin Surya Pranata - 1 year, 6 months ago

That's not arbitrage

padraic mellett - 9 months, 1 week ago

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