Probability at its best!

Probability Level pending

Consider a function f ( x ) = { { x } + n , 2 n x < 2 n + 1 x n , 2 n + 1 x < 2 n + 2 f(x) = \begin{cases} \{ x \} + n , 2n \leq x < 2n + 1 \\ \lfloor x \rfloor - n , 2n + 1 \leq x < 2n + 2\end{cases} for integer n n .

A point M = ( x , y ) M = (x,y) is selected at random where 0 x 6 0\leq x \leq 6 and 0 y f ( x ) 0 \leq y \leq f(x) .

If the perpendicular distance of M M from the x x -axis is smaller than its perpendicular distance from f ( x ) f(x) , then the probability that 3 x 4 3\leq x \leq 4 is given by 2 a ( 3 b 1 ) \dfrac2{a\left(3\sqrt b - 1\right)} , where a a and b b are positive integers.

Find the value of b a |b-a| .


The answer is 1.

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1 solution

Avi Solanki
Apr 26, 2017

@Pi Han Goh sir what is your method ?

avi solanki - 4 years, 1 month ago

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