Probability

Let 0 < x < 1 6 0 < x < \frac{1}{6} be a real number. When a certain biased dice is rolled, a particular face F F occurs with a probability 1 6 x \frac{1}{6} - x and its opposite face occurs with a probability 1 6 + x \frac{1}{6} + x ; the other four faces occur with probability 1 6 \frac{1}{6} . Recall that the opposite faces sum to 7 7 in any dice. Assume that the probability of obtaining the sum 7 7 when two such dice are rolled is 13 96 \frac{13}{96} . Then the value of x x is :

1 24 \frac{1}{24} 1 12 \frac{1}{12} 1 8 \frac{1}{8} 1 4 \frac{1}{4}

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