The probability that Danny wins a game is twice the probability that Arin wins a game. If each game is independent (that is, the outcome of one game does not affect another), the probability that Danny wins exactly two games out of five is where and are relatively prime positive integers.
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Let us assume there is no draw in a game.
So, in 1 game,
P(Danny win)=2/3
P(Arun win)=1/3
In 5 games,
P(Danny-2, Arun-3)=5C2 (2/3)²(1/3)³
=40/243=a/b
a+b=283