Probability - Home Field Advantage

In a game between two equal teams, the home team wins any game with probability P. In a best of three playoff series, a team with the home advantage has a game at home, followed by a game away, followed by a home game if necessary. The series is over as soon as one team wins two games. What is the probability that the team with home advantage wins the series ? Is the home advantage increased by playing a three-game series rather than one-game play-off ?

1 0.50 2 0.75

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1 solution

Aditya Raj
Dec 24, 2014

Let's say probability of home team winning is P. Let Q = 1 -P, probability of visiting team winning.

In a one-game playoff, it's simple, whichever team is the home has probability P of winning.

With three games, there are few enough cases to examine them one by one.

Let's call the team that has the first (and possibly third) home game H and the other team V.

The possible outcomes, denoted by which team wins each game are:

H H with probability P x Q H V H with probability P x P x P V H H with probability Q x Q x P

V V with probability Q x P V H V with probability Q x Q x Q H V V with probability P x P x Q

In the extreme case, if P = 1 and Q = 0 (or the reverse), there will only be one case: H V H and the probability will be 1 x 1 x 1 or 1.

In the case P = Q = 1/2, the terms are H H 1/4 H V H 1/8 V H H 1/8 and these add to 1/2, as do the other three cases.

All other cases fall between these two.

The overall advantage goes to whichever team has more of the higher of P and Q. If P > 1/2, H has the advantage, if P < 1/2, V has the advantage.

Let's try an example, and say P = 3/4 and Q = 1/4 Then we have: H H : P x Q ~= .188 H V H: P x P x P ~= .422 V H H: Q x Q x P ~= .047 These add to .657

V V: Q x P ~= .188 V H V: Q x Q x Q ~= .016 H V V: P x P x Q ~= .141 These add to .345 (Altogether slightly more than 1.000 due to rounding errors.)

So if the home-field advantage for one game is .75 / .25, the advantage in a 3-game series is reduced to around .66 / .33.

Similarly, the closer the one-game advantage is to 1/2, the closer to 1/2 the three-game advantage will be.

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