Probability involved π \pi ?

What is the probability that two numbers selected at random are relatively prime?

π 6 \dfrac{\pi}{6} 90 π 4 \dfrac{90}{\pi^4} 6 π 2 \dfrac{6}{\pi^2} 2 π \dfrac{2}{\pi} 945 π 6 \dfrac{945}{\pi^6} π 2 90 \dfrac{\pi^2}{90}

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1 solution

Tommy Li
Oct 2, 2017

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