Probability of Winning

Probability Level 2

I have a game where the chance of winning (unbiased) is 1 60 \frac{1}{60} . What is the chance of me winning at least once if I play the game only 20 20 times?

NOTE: Answer in decimal form and in the nearest ten thousandths.


The answer is 0.2854786252.

Kaizen Cyrus by Kaizen Cyrus , 18, Philippines

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1 solution

Kaizen Cyrus
Sep 3, 2020

The chance of losing when playing 20 20 times on the game is ( 59 60 ) 20 (\frac{59}{60})^{20} . Subtract it from 1 1 and we get the chance of winning.

1 − ( 59 60 ) 20 = 0.28547... 1 - \left(\dfrac{59}{60}\right) ^{20} = \boxed{0.28547...}

3 Helpful 1 Interesting 2 Brilliant 0 Confused

This is the chance of winning at least once. Not really clear from the way the problem is stated.

Peter van der Linden - 9 months, 1 week ago

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