Probability with exponentials

Calculus Level pending

Find the probability that a b < 0.9 a^b\lt 0.9 for two variables a , b a,b that are both restricted to the domain [0,1]. Round your answer to 3 decimal places.

Bonus: Generalize this probability for any real value between 0 and 1.


The answer is 0.287.

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1 solution

a b < 0.9 a^{b} < 0.9 a < 0. 9 1 b a < 0.9^{\frac{1}{b}} Using geometric probability we can graph an a a versus b b graph on the interval [ 0 , 1 ] [0,1] , noting that a a is our independent variable and b b is our dependent variable. Then we find the area under the curve of this inequality. Due to the variables being switched in the equation in relation to our graph, we must take one minus that area. 0 1 0. 9 1 x = 0.7129 \int_{0}^{1} 0.9^{\frac{1}{x}} = 0.7129 These types of integrals are non-elementary and can only be solved by numerical methods. Thus, the answer is 1 0.7129 = 0.287 1-0.7129 = \boxed{0.287}

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