Probably or what?
What is the probability that the number of Sundays in a normal year is 53?
Details and assumptions:
1) You will get the answer in the form where and are positive co-prime numbers.
2) Provide the answer as .
The answer is 8.
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As we know ,
In an ordinary year there are 365 days.
Therefore, we have 365 days = 52 weeks and 1 day.
Thus, an ordinary year has always 52 Sundays.
Then, the remaining 1 day can be :
(i) Sunday (ii)Monday (iii)Tuesday (iv)Wednesday (v) Thursday (vi)Friday (vii) Saturday
Clearly, there are seven elementary events associated with this random experiment.
Let A be the event that an ordinary year has 53 Sundays.
Clearly, there is only one chance that the remaining day will be sunday
Favourable number of elementary events = 1
Hence, Required Probability = 1/ 7
a+b=1+7=8