probablyyyyyy
in a multiple choice question there are four alternative answers, of which one or more are correct. a candidate will get marks in the question only if he ticks all the correct answers. the candidate decides to tick answers at random. if he is allowed up to three chances to answer the question find the probability that he will get marks in the question..
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
the total no of ways of ticking the answers in any one attempt is 2/\4 -1 is 15. the student is taking chance at ticking the correct solution. therefore, It is reasonable to assume that in order to derive maximum benefit, the three solutions which he will submit will be all different hence, total no of ways is 15C3.. the no of ways in which the correct solution is excluded is 14c3. THE required PROBABILITY IS 1-(14C3/15C3) IS 1/5