Tessellate S.T.E.M.S - Physics - School - Set 1 - Problem 4
The image of an illuminated square is obtained on a screen with the help of a converging lens. The distance of the square from their lens is . the area of the rectangle is times the length of the square. The focal length of the lens is
This problem is a part of Tessellate S.T.E.M.S.
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1 solution
(1÷f)=(1÷v)+(1÷u) now if the area is 9 times then the side is 3 times. Again the ratio of the size of object and image is equal to the ratio of their distance from the lens. From there we get image distance is 120 cm. Now put this value in the above formula. We get f=30.