Problem 10
Probability
Level
2
A group of 3 men and 4 women is to be selected from 6 men and 7 women. Find the number of ways the groups can be formed if the order doesn't matter.
Check out the set: Combinatorics .
The answer is 700.
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1 solution
The number of ways to choose 4 women out of 7:
( 4 7 ) = 3 5
The number of ways to choose 3 women out of 6:
( 3 6 ) = 2 0
By combining these choices, we get:
3 5 × 2 0 = 7 0 0