Problem

Algebra Level 3

What is the last digit of 2 4 6 8 \large 2^{4^{6^8}} ?

4 3 2 6 1

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1 solution

Manuel Kahayon
Dec 28, 2015

This isn't algebra... It's number theory... Anyways... If 2 4 k 2^{4k} for all natural numbers k, then the last digit will always be 6.

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