Given that and are positive reals satisfying , find the minimum value of the expression above.
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Since the second equation is symmetric in y and z, I assumed y = z and after solving you will get x = 4y = 4z. Substituting in the first equation we will get a simple cubic whose minima (and minimum as x, y, and z are positive) occurs at (4, 1, 1). Thus the answer is -64.