Problem #7

Algebra Level 1

Find x, given that:

x 2013 + x 2014 + x 2015 = 2 \left| x-2013 \right| +\left| x-2014 \right| +\left| x-2015 \right| =2

Authentic test problem - 1st term test - 2014-15 (Hanoi-Amsterdam high school)


The answer is 2014.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

There is a mathematical property: a + b a + b \left| a \right| +\left| b \right| \ge \left| a+b \right| So 2 = x 2013 + x 2014 + x 2015 = x 2013 + x 2014 + 2015 x x 2013 + 2015 x + x 2014 2 + x 2014 0 x 2014 x 2014 = 0 x = 2014 2=\left| x-2013 \right| +\left| x-2014 \right| +\left| x-2015 \right| =\left| x-2013 \right| +\left| x-2014 \right| +\left| 2015-x \right| \\ \ge \left| x-2013+2015-x \right| +\left| x-2014 \right| \\ \ge \left| 2 \right| +\left| x-2014 \right| \\ \Rightarrow 0\ge \left| x-2014 \right| \\ \Rightarrow x-2014=0\\ \Rightarrow x=2014 Note that since x 2014 0 \left| x-2014 \right| \ge 0 so we can immediately say x 2014 = 0 x-2014=0 without proving anything.

it is easy to guess 2014..

Vighnesh Raut - 6 years, 5 months ago

Log in to reply

Yes. This task is worth 0.5pts/10pts, which is only 5% of the score. And by guessing 2014, you'll get 0.25pts. But what I want to do here is for everyone to think logically about the answer, not to guess. If we do that at class, the teacher will not accept that answer since you haven't proved anything that 2014 is the answer. Anyway, it's easy to guess =))

Đức Dũng Phạm - 6 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...