Problem Dated 30.05.21

Algebra Level 3

If there exists a function f ( x ) f(x) such that it always takes some positive value and there exists two positive integers p p and q q such that

f ( x f ( y ) ) = x p y q x , y R + f(xf(y)) = x^p y^q \quad \forall x, y \in \mathbb R^+

Find the value of ( log q p ) 3 . ( \log_{q} {p})^{3}.


The answer is 0.125.

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1 solution

Here by putting x f ( y ) = 1 xf(y) = 1 , we get

f ( 1 ) = x p . y q f(1) = {x}^{p}.{y}^{q}

f ( 1 ) = y q ( f ( y ) ) p f(1) = \frac{{y}^{q}}{({f(y)})^{p}}

f ( 1 ) = 1 ( f ( 1 ) ) p f(1) = \frac{1}{({f(1)})^{p}} [by putting y = 1 y=1 ]

( f ( 1 ) ) p + 1 = 1 (f(1))^{p+1} =1 f ( 1 ) = 1 \implies f(1) = 1 ..............(1)

f ( x f ( 1 ) ) = f ( x ) = x p f(xf(1)) = f(x) = {x}^{p} ..............(2)

f ( x f ( y ) ) = x p . ( f ( y ) ) p = x p . y p 2 = x p . y q f(xf(y)) = {x}^{p}.(f(y))^{p} = {x}^{p}.{y}^{{p}^{2}} ={x}^{p}.{y}^{q} (given)

q = p 2 q = p^{2}

Thus ( l o g q p ) 3 = 1 8 = 0.125 (log_q{p})^{3} = \frac{1}{8} = 0.125

Hope this helps.:)

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