If there exists a function such that it always takes some positive value and there exists two positive integers and such that
Find the value of
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Here by putting x f ( y ) = 1 , we get
f ( 1 ) = x p . y q
f ( 1 ) = ( f ( y ) ) p y q
f ( 1 ) = ( f ( 1 ) ) p 1 [by putting y = 1 ]
( f ( 1 ) ) p + 1 = 1 ⟹ f ( 1 ) = 1 ..............(1)
f ( x f ( 1 ) ) = f ( x ) = x p ..............(2)
f ( x f ( y ) ) = x p . ( f ( y ) ) p = x p . y p 2 = x p . y q (given)
q = p 2
Thus ( l o g q p ) 3 = 8 1 = 0 . 1 2 5
Hope this helps.:)