Problem for intermediators
Algebra
Level
2
If log 2 = 0.301, log 3 = 0.477,find no. of digits in 6^31.
25
26
24
None of these
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1 solution
Let the number be n. Then number of digits in that number is given by :
[ ( lo g 1 0 n ) ] + 1
where [.] is Greatest Integer Function.