Problem for Medium Levels

Algebra Level 2

If x is real then minimum value of x 2 8 x + 17 { x }^{ 2 }-8x+17

None of these 17 12 8 5 10

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1 solution

Brian Wang
Oct 28, 2015

To find to minimum value, you can put it in vertex form.
x 2 8 x + 17 = y {x}^{2}-{8}{x}+{17}={y}
x 2 8 x + 16 + 1 = y {x}^{2}-{8}{x}+{16}+{1}={y}
( x 4 ) 2 = y 1 {(x-4)}^{2}={y}-{1}
So the vertex is (4,1)
Because the coefficient of x 2 {x}^{2} is positive, the parabola opens upwards. Therefore, the minimum value of the equation is x=4, y=1 or 1. So the answer choice is "None of these"

Or just ( x 4 ) 2 0 (x-4)^2 \geq 0 .

Nihar Mahajan - 5 years, 7 months ago

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Exactly i did same

Aditya Kumar - 5 years, 1 month ago

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