If 2 2 0 2 0 − 2 2 0 1 9 − 2 2 0 1 8 + 2 2 0 1 7 = k × 2 2 0 1 7 , find k .
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⇒ 2 2 0 2 0 − 2 2 0 1 9 − 2 2 0 1 8 + 2 2 0 1 7 = k × 2 2 0 1 7
2 2 0 1 7 2 2 0 1 7 ( 2 3 − 2 2 − 2 1 + 2 0 ) = k
2 3 − 2 2 − 2 + 1 = k
8 − 4 − 2 + 1 = k
∴ k = 3
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2 2 0 2 0 − 2 2 0 1 9 − 2 2 0 1 8 + 2 2 0 1 7 = 2 2 0 1 7 ( 2 3 − 2 1 − 2 2 + 2 0 ) = 3 × 2 2 0 1 7 ∴ k = 3