Problem For Year 2016

Find the smallest positive integer that leaves a remainder of 1 when divided by each of 5, 13 and 31.


The answer is 1.

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1 solution

Grant Bulaong
Aug 1, 2016

That's right, the answer isn't 2016. Did you get it in one try?

This post is dedicated to my friends who recently participated in international competitions.

Everyone hates you that question

Norwyn Kah - 4 years, 10 months ago

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