Problem from Art of problem solving

Algebra Level 2


The answer is 12.

Jyothiraditya Datta Poduri by Jyothiraditya Datta Podu… , 17

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1 solution

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Jun 28, 2018

4 2 3 2 1 6 3 3 2 2 − 1 2 3 1 2 = 2 4 3 2 1 6 3 3 2 2 − 1 2 3 1 2 = 2 ( 4 3 + 1 6 + 1 2 ) × 3 ( 3 2 − 1 2 ) = 2 2 × 3 = 12 \large\dfrac{4^{\frac23}2^{\frac16}3^{\frac32}}{2^{-\frac12}3^{\frac12}}=\dfrac{2^{\frac43}2^{\frac16}3^{\frac32}}{2^{-\frac12}3^{\frac12}}=2^{(\frac43+\frac16+\frac12)}\times3^{(\frac32-\frac12)}=2^2\times3=12

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