Problem no. 21

Geometry Level 2

log tan 1 o + log tan 2 o + + log tan 8 9 o = \large \log{\tan{1^o}}+\log{\tan{2^o}}+\ldots +\log{\tan{89^o}}=\ldots

0 0 3 3 \frac{\sqrt{3}}{3} 1 1 3 \sqrt{3} \infty

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1 solution

Venkata Teja B
Mar 30, 2015

tan89 = cot1

log(tan88)=log(cot2)=-logtan2

only log(tan45) remains which is equal to zero

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