Problem No. 44

How many three digit positive integers are there, the sum of whose digits is a perfect cube?


The answer is 38.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Greatest three digit integer is 999 = 3 3 999=3^3 . So only we can have 1^3=1,~~~2^3=8,~~~3^3=27.\\ 1^3=~1=1+0+0,~that~ is~ 100~~ONLY.\\ 3^3=27=9+9+9,~that ~is~ 999~~ONLY.\\ 2^3=~8~has~many~options.\\ Left~ digit~~1,.~middle~can~be~0~to~7,~~~8~~options, right ~no~option. \\ Left~ digit~~2,.~middle~can~be~0~to~6,~~~7~~options, right ~no~option. \\ ' ' ' ' ' ' '\\ ' ' ' ' ' ' '\\ Left~ digit~~8,.~middle~can~be~0~Only,~~~1~~options, right ~no~option. \\ So ~total=~1+1+8+7+6+5+4+3+2+1=2+\dfrac{8*9} 2=~~~\Large \color{#D61F06}{38}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...