Problem of the week

Algebra Level 3

The minimum value of f ( x ) f(x) is

f ( x ) = 1 2 [ − x ] + [ − x ] f(x) = \dfrac{1}{2[-x]} + [-x]

Details:

  • [x] denotes fractional part of x
2 \sqrt2 +1 2 2 \sqrt2 2 \sqrt2 2 \sqrt2 - 1

Akhil Bansal by Akhil Bansal , 22, India

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2 solutions

Aman Deep Singh
Dec 20, 2015

4 Helpful 0 Interesting 0 Brilliant 0 Confused
Stephanie T
Apr 1, 2020

Find the derivative of the function and that will give you the value of [-x]. Plug that value back into the original function and you have your answer but make sure to simplify the radical.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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