Problem on probalility
An article manufactured by a company consists of two parts A and B. In the process of manufacturing Part A, 9 out of 100 are likely to be defective. Similarly, 5 out of 100 are likely to be defective in the manufacture of Part B. Calculate the probability that the assembled article will not be defective(assuming that the events of finding the Part A non defective and that of B are independent).
The answer is 0.86.
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1 solution
Answer
= P(perfectly manufactured product)
= P(neither parts are defective)
= [ 1 - P(defective part A) ] × [ 1 - P(defective part B) ]
= ( 1 - 9/100 ) × ( 1 - 5/100 )
= 0.91 × 0.95
= 0.8645
= 86.45%