Problem with animals


Paul lined up his animals in a farm. In front of a p i g pig is a d o g dog and a s h e e p sheep . Behind a c a t cat is a p i g pig , d o g dog , and s h e e p sheep . In front of a s h e e p sheep is a c a t cat , a p i g pig , and a d o g dog .


  • Question 1: If there are as few animals as possible, what animal is directly in front of a cat?
  • Question 2: If Paul has as few animals as possible, how many of each animal does he have?

P i g Pig = 1

C a t Cat = 2

S h e e p Sheep = 3

D o g Dog = 4

N o n e None = 5

I n d e t e r m i n a t e Indeterminate = 0


Your answer to question 1 should be the assigned value of the animal that is directly in front of a c a t cat . The answer is none if you think no animal is in front of a cat. If you think that there are multiple cats, and each one has a different animal in front of it, then just answer indeterminate.

Your answer to question 2 should be the sum of values of all the animals that Paul owns. That is, if your answer is 300 300 pigs, 17 17 dogs, 30 30 cats, and 12 12 sheep, then your answer should be ( 300 × 1 ) + ( 30 × 2 ) + ( 12 × 3 ) + ( 17 × 4 ) = 464 (300 \times 1)+ (30 \times 2) + (12 \times 3) + (17 \times 4) = 464 .

If your answer to question 1 is x x , and your answer to question 2 is y y , input your answer as x × y x \times y .






This problem is an adaptation.


The answer is 50.

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1 solution

Efren Medallo
Jun 9, 2015

Note that it was not specified whether the animals are all facing in the same direction.

Therefore we can arrange the animals in this manner:

Thus, we get our answer to question 1 as 5 5 , because there is no animal in front of the cat. As for question 2, since there are just 1 1 of each animal, then our answer is 10 10 .

And so, for the final answer, we get 5 × 10 = 50 5 \times 10 = \boxed{50} .

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