Problems with wedges (1)

In the figure shown above, a ball of mass m m collides perpendicularly with constant velocity u u on a smooth stationary wedge of mass M M with inclination θ \theta kept on a smooth horizontal plane. If the coefficient of restitution of collision is e e , then determine the velocity of the wedge after collision.

Details:

  • Assume gravity has no effect on the ball of mass m m until it collides with the wedge and during its collision.

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( 1 e ) m u sin θ M + m cos 2 θ \dfrac{\left(1-e\right)mu\sin\theta}{M+m\cos^{2}\theta} ( 1 + e ) m u sin θ M + m cos 2 θ \dfrac{\left(1+e\right)mu\sin\theta}{M+m\cos^{2}\theta} ( 1 e ) m u sin θ M + m sin 2 θ \dfrac{\left(1-e\right)mu\sin\theta}{M+m\sin^{2}\theta} ( 1 + e ) m u sin θ M + m sin 2 θ \dfrac{\left(1+e\right)mu\sin\theta}{M+m\sin^{2}\theta}

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2 solutions

Arshad Sparrow
Oct 2, 2017

Every question on this site matches the questions of FIITJEE package.

Not this site, it's me who posted this problem. And yes it's from FIITJEE package only.

Tapas Mazumdar - 3 years, 8 months ago

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Can u please tell me how to do it

aditya mutharia - 3 years, 8 months ago

Yes you are right

Aniket kumar - 3 years, 8 months ago

Hey can u please explain the answer to this question to me..

aditya mutharia - 3 years, 8 months ago
Pratyush Pandey
Oct 7, 2016

Since this is an objective, putting e=1 and theta=90 will give you the answer by elimination. I know this isn't the solution you might be looking for but I don't know how to write one..

no it's a good one i did it too ! good for jee !

hiroto kun - 4 years, 5 months ago

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