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Algebra Level 3

∏ n = 1 ∞ n 3 − 1 n 3 + 1 = ? \large \displaystyle \prod_{n=1}^{\infty} \dfrac{n^3-1}{n^3+1}~=~?

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The answer is 0.

Rohit Udaiwal by Rohit Udaiwal , 20, India

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1 solution

Rohit Udaiwal
Jan 19, 2016

∏ n = 1 ∞ n 3 − 1 n 3 + 1 = 0 1 ⋅ 7 9 ⋅ 26 28 … = 0 \large \displaystyle \prod_{n=1}^{\infty} \dfrac{n^3-1}{n^3+1} \\ =\dfrac{0}{1}\cdot \dfrac{7}{9}\cdot\dfrac{26}{28}\ldots \\ =\boxed{0}

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This problem was made accidentally while solving this .

Rohit Udaiwal - 5 years, 4 months ago

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