Product minus sum

How many unordered pairs of positive integers { a , b } \{a,b\} have the property that their product minus their sum is equal to 11 11 ?

(The pairs { a , b } \{a,b\} and { b , a } \{b,a\} are the same.)

0 3 1 2

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1 solution

Aaron Tsai
Apr 25, 2016

We can set up the equation a b ( a + b ) = 11 ab-(a+b)=11 . Adding 1 1 to both sides we get

a b a b + 1 = 12 ab-a-b+1=12

( a 1 ) ( b 1 ) = 12 (a-1)(b-1)=12

The pairs of factors of 12 12 are ( 1 , 12 ) (1,12) , ( 2 , 6 ) (2,6) , and ( 3 , 4 ) (3,4) . Therefore, there are 3 \boxed{3} unordered pairs { a , b } \left \{ a,b \right \} that have the property that their product minus their sum is 11 11 .

Nice solution. Note that if ( a , b ) (a,b) and ( b , a ) (b,a) are the same, then they are known as unordered pairs. I have edited the problem accordingly.

You can use \boxed{3} to create a box around 3.

Pranshu Gaba - 5 years, 1 month ago

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