Jesse rolls two fair 6-sided dice. What is the probability that the product of the faces is at least 6?
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There are 36 possible outcomes of rolling the two fair 6-sided dice. (because of 6 x 6 or 6^2)
By listing all the possible outcomes:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Since the problem asks for the probability that the product of the faces is at least 6, you may notice that there are 26 possibilities that show the favored outcome which are:
(1,6)
(2,3) (2,4) (2,5) (2,6)
(3,2) (3,3) (3,4) (3,5) (3,6)
(4,2) (4,3) (4,4) (4,5) (4,6)
(5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
By counting them, you are able to get 26 favored outcomes
Because of the formula: Number of favorable outcomes/Total number of possible outcomes;
the probability is 26/36 = 13/18